What is the center of the circle whose equation is x2 y2 2x 4y 11?
Find the center and radius of the circle with equation x2 + y2 + 2x – 4y – 11 = 0. Then graph the circle. Complete the square. The center of the circle is at (–1, 2), and the radius is 4.
What is the radius of of a circle in the equation x 2 y 2 2x 4y 20 0?
This is a circle with centre (1,2) and radius 5 .
What is the center radius form of a circle defined by x 2 y 2 − 2x 4y − 1 0?
x²+y²–2x+4y+1=0. =>x²–2x+1 +y²+4y+4+–1–4+1=0. =>(x–1)² +(y+2)²=2² Therefore, centre of the circle (1,–2) and radius 2 unit.
What are the center and radius of a circle whose equation in general form is x2 − 2x y2 2y − 23 0?
The center C of the given circle: x² + y² −2x − 2y − 23 = 0 is clearly (1, 1), and radius r = √(1+1+23)= 5, therefore its area A = πr² = 25π .
Which is the equation of a circle with center 2 1 that passes through 2 4?
Which is the equation of a circle with a center (2, 1) that passes through (2 and 4)? Equation of circle: (x – h)^2 + (y – k)^2 = r^2 where (h, k) is the center and r is the radius.
What are the coordinates of the center and the radius of the circle with equation?
The formula for the equation of a circle is (x – h)2+ (y – k)2 = r2, where (h, k) represents the coordinates of the center of the circle, and r represents the radius of the circle. If a circle is tangent to the x-axis at (3,0), this means it touches the x-axis at that point.
Which of the following could be used to calculate the area of the sector in the circle shown above?
Summary: To calculate the area of the sector in the circle shown, π(15in)2 40 over 360° can be used.
What is the Centre of a circle?
The center of a circle is the point equidistant from the points on the edge. Similarly the center of a sphere is the point equidistant from the points on the surface, and the center of a line segment is the midpoint of the two ends.
Which is the equation of a circle with center 2?
The equation of a circle with center (h,k) and radius r units is (x−h)2+(y−k)2=r2 .